Question

An engine pumps up 100kg of water through a height of 10m in 5s. If the efficiency of the engine is 60%, what is the power of the engine? Take g=10ms^–2

Answer 1

Answer:

Correct option is

B

3.3 kW

Given,

Weight=100kg

height=10m

t=5s

effeciency=60%

g=10m/s2

So the output power is 

tmgh=5100kg×10m/s2×10=2kw

Now,

The Effeciency=input−poweroutput−power×100⇒60=input2×100⇒=Input=3.33kw

Explanation:

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