Question

An engine pumps up 200kg of water through a height of 20m in 20 sec. The efficiency of the engine is 50% , what is the power of the engine ? (g=10m/ second square) 

irrelevant answers will be reported ​

Answer 1

Answer:

Weight=100kg

height=10m

t=5s

effeciency=60%

g=10m/s  

2

 

So the output power is  

t

mgh

​  

=  

5

100kg×10m/s  

2

×10

​  

=2kw

Now,

The Effeciency=  

input−power

output−power

​  

×100⇒60=  

input

2

​  

×100⇒=Input=3.33kw

Explanation:

Answer 2

Answer:

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