Question

An engine pumps water continuously through a hose. Water leaves the hose with a velocity v an m is the mass per unit length of the water jet. What is the rate which kinetic energy is imparted to water ?

Answer 1

hey friend!

this is your answer--

MV^3/2

let m is the mass per unit length rate of mass
per second = mx/t=mv

rate of kE = (mv) v^2/2 =mv^3/2

Let m is the mass per unit length rate
of mass per second = mx/t=mv

Rate of KE = (mv) v^2/2 = MV^3/2

Answer 2

Answer:last step :d (KE)by dt equalsto half mv v ^2 equalsto half m v cube

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