Question

An engine pumps water having value 20meter cube raise it up to a height of 60 m in a time of 5 minutes efficiency of the engine is 50% find out power consumed by the engine?​

Answer 1

Answer:

$80 \times {10}^{3} \: W$

Explanation:

Given

Volume = 20 m^3

Time = 5min = 5 X 60 = 300 seconds

Efficiency of the engine = 50%

To find

Power consumed which means we need P input.

We know that

$\boxed{ \% \: n = \frac{P_{output}}{P_{input}} \times 100}$

and

$\boxed{P_{output} = \frac{w}{t} = \frac{mgh}{t} }$

On putting all values

$P_{output} = \frac{ {10}^{3} \times 20 \times 10 \times \times 60 }{300} \\ P_{output} = \frac{ {10}^{3} \times 20 \times 10 \times \cancel60 }{ \cancel300} \\ P_{output} = \frac{ {10}^{3} \times 20 \times \cancel10 \times 1 }{ \cancel5} \\ \boxed{\ P_{output} = 40 \times {10}^{3} }$

Now

According to Question

$= > 50 = \frac{P_{output}}{P_{input} } \times 100 \\ = > \cancel50 = \frac{40 \times {10}^{3} \times \cancel100 }{P_{input}} \\ = > \boxed{P_{input} = 80 \times {10}^{3} \: W }$

Therefore

Power consumption of the Engine will be 40 X 10^3 W.

Answer 2

Mechanical Properties of Fluids :

Power :

Answer : Power consumed = 80 × 10^3 W

Explanation :

Refer the attached picture.