Question

An engine requires 5 seconds to go from a speed 600 r.p.m. to 1200 r.p.m. What is its angular acceleration?​

Answer 1

Given: Initial speed of the engine(ω1)= 600 r.p.m

           Final speed of the engine(ω2)=1200 r.p.m

        Time required to achieve the final speed =5 seconds

To Find: Angular acceleration of the engine(α)

Solution: Angular acceleration(α)=Δω/Δt

         The difference between angular velocity when divided with time will give the angular acceleration.

Here angular velocity is the speed of the engine.

                  α=ω2-ω1/t2-t1

                  α=1200-600/5

                  α=600/5

                  α=120 radians/sec

Therefore the angular acceleration is 120 radians per second