Physics, asked by mahuya7522, 5 months ago

An engineer claims that he has developed 60% efficient engine while working between 270c and 3270C. Does his claim stands?

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
10

Given

  • Sink temp(T₂) = 27°C = 300k
  • Source temp (T₁) = 327°c = 600k
  • Efficiency = 60%

To Find

  • If the given information hold true

Solution

☯ Efficiency = 1 - T₂/T₁

  • Where T₂ here will be 300 k & T₁ will be 600 k

━━━━━━━━━━━━━━━━━━━━━━━━━

According to the Question :

→ η = 1 - T₂/T₁

→ η = 1 - 300/600

→ η = 600-300/600

→ η = 300/600

→ η = 3/6

→ η = 0.5

━━━━━━━━━━━━━━━━━━━━━━━━━

Converting to %

→ 0.5 × 100

→ Eta = 50%

∴ The information given doesn't hold true


TheValkyrie: Amazing :fb_wow:
Answered by BengaliBeauty
17

Answer:-

 \small \bf \underline{Given:}

★★ Efficiency = 60%

★★ Sink temperature =   \small \bf  T_2= 27 + 273 = 300K

★★ Source temperature =   \small \bf  T_1 = 327 + 273 = 600K

 \small \bf \underline{To  \: find:}

We need the find that whether the given information is true or false

 \small \bf \underline{Solution:}

» Possible efficiency =

 \small \bf1 -  \frac{T_2}{T_1}

 \bf =( 1 -  \frac{300}{600} )\%

 \bf = (1 -  \frac{1}{2} )\%

 \bf =  \frac{1}{2} \%

 = 50\%

Answer: The information given by the engineer doesn't hold true.

@BengaliBeauty

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