an engineer designed a turn on the road so that a 1225 kg car would need 4825 N of centripetal force when traveling around the curve at 72.5 km/h. what is the radius of the curvature of the road? watch your units
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Answer:
72.5 km/h = 72.5*1000/3600 = 20.1388889
1225 kg = 1225000 g
Centripetal force
Fc = mv^2/r
4825 = 1225000*(20.14*20.14)/r
r = 1225000*405.57/4825
= 496,829,186/4825
= 102,969.779
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