An engineer is designing the run way for airport of the planes that will use the airport,the lowest acceleration rates is likely to be m/s. the take off speed for this plane will be 65m/s. Assuming this minimum acceleration, What is the minimum allowed length for the runway
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Answer:
The answer is 704 m
Explanation:
Given, initial velocity, u=0m/s and final velocity v=65m/s
Acceleration a=3m/s
2
If d be the allowed length for the runway.
Using formula v
2
−u
2
=2aS
(65)
2
−0
2
=2(3)d
⟹ d=65
2
/6=704.16∼704m
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