Physics, asked by gyftseth, 8 months ago

An engineer is designing the runway for an airport of planes that will use the airport,the Lowest acceleration rate is likely to be 3 m/s². The take off speed for this plane will be 65 m/ s² , assuming this minimum acceleration, what is the minimum allowed length for the runway ?

Answers

Answered by dhruvbadaya1
3

Answer:

704.16 m

Explanation:

Given, initial velocity, u=0m/s and final velocity v=65m/s

Acceleration, a=3 m/s^{2}  

Let d be the allowed length for the runway

Using formula,  

v^{2}-u^{2}=2aS

65^{2} -0^{2} =2(3)d

d=65^{2} / 6

d= 704.16 m

Similar questions