Question

An engineer is designing the runway for an airport of planes that will use the airport,the Lowest acceleration rate is likely to be 3 m/s². The take off speed for this plane will be 65 m/ s² , assuming this minimum acceleration, what is the minimum allowed length for the runway ?

Answer 1

Answer:

704.16 m

Explanation:

Given, initial velocity, u=0m/s and final velocity v=65m/s

Acceleration, $a=3 m/s^{2}$  

Let d be the allowed length for the runway

Using formula,  

$v^{2}-u^{2}=2aS$

$65^{2} -0^{2} =2(3)d$

$d=65^{2} / 6$

d= 704.16 m