An engineer is designing the runway for an airport of planes that will use the airport, the Lowest acceleration rate is likely to be 3 m/s² . The take off speed for this plane will be 65 m/s , assuming this minimum acceleration, what is the minimum allowed length for the runway ?
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Answer:
704.16 metre
Explanation:
u = 0 m/s
v = 65 m/s
a = 3 m/s^2
by using equation, v^2 - u^2 = 2*a*s
s = (65^2 - 0) / 2*3
= 704.16 mt
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