Question

an engineer is designing the runway for an airport. of the planes that will use the airport , the lowest accelaration rate is likely to be 3 m/s2 . the take off speed for this plane will be 65 m/s . assuming this minimum acceleration , what is the minimum allowed length for the runway ?

Answer 1

s is the length of the runway.
initial velocity = 0 = u
final velocity = 65 m/s = v
minimum acceleration = a = 3 m/sec²

v = u + a t  =>  t = v/a = 65/3 sec
s = u t + 1/2 a t² = 1/2 * 3 * 65²/3² = 704.6 meters
    
if the acceleration is more than 3 m/sec,  then s = v² / (2a)    will be shorter.

Answer 2

Answer:

hope it wilp help u all.....