Question

An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The takeoff speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length for the runway?​

Answer 1

Your answer is d = 704 m

Process:

Given:

vi = 0 m/s

vf = 65 m/s

a = 3 m/s2

Find:

d = ??

vf2 = vi2 + 2*a*d

(65 m/s)2 = (0 m/s)2 + 2*(3 m/s2)*d

4225 m2/s2 = (0 m/s)2 + (6 m/s2)*d

(4225 m2/s2)/(6 m/s2) = d

d = 704 m