Question

An engineer works at a factory out of town..a car is sent for him from the factory everyday and arrives at railway station at same time.one day the engineer arrived at the station one hour before his usual time and without waiting for the car,started walking towards factory.on his way he met the car and reached his factory 10 minutes before the usual time..for hum much time did the engineer walk before he met the car.the car moves with the same speed everyday??

Answer 1

Hi thank you for asking the question
suppose the man reaches to work in the car by travelling in one hr = 60 mins
Now the next day he reaches the place one hr before ( another 60 mins) at his place and and started walking and traveled the car and reached 10 mins before the usual time so 120 mins ( 2 hrs) - 10 mins he saved = 110 mins 
In car if the time taken to reach the place is 1 hr so 110 - 60 mins = 50 mins 
So the guy walked for 50 mins and then entered the car and it took 60 mins more to reach the place of work
Kindly recheck to see if answer is correct
Thanks

Answer 2

A engineer works at a plant out of town. A car is sent for him from the plant every day and this car arrives at the railway station at the same time as the train he takes. One day the engineer arrived at the station 60 minutes before his usual time and without waiting for the car, started walking to work. On his way he met the car and reached his plant 10 minutes before the usual time. The time duration for which the engineer walk before he met the car is time reached before-half the time he saved as the car is travelling a two way journey. 60-5=55 mins.