Question

an engineering student has to secure 45%marks to pass. he gets 54 and fails by 36marks. find the max. marks

Answer 1

45÷100×36÷54

=30

I hope this helps you...

Answer 2

Answer:

The maximum marks is 200.

Step-by-step explanation:

Given : An engineering student has to secure 45%marks to pass. He gets 54 and fails by 36 marks.

To find : The maximum marks ?

Solution :

Marks he get = 54

He got failed by 36 marks

Passing marks = 54+36=90

Let the maximum marks be 'x'.  

An engineering student has to secure 45% marks to pass.

i.e. $45\% \times x = 90$

$\frac{45}{100} \times x = 90$

$x=\frac{90\times 100}{45}$

$x=200$

Therefore, The maximum marks is 200.