Question

An entrance examination for admission to a first degree course in medicine was conducte at the national leel. The mena and standard deviation of the marks obtained by 15000 canidates were 40 and 8 respectively. Determine in terms of standard deviation, the standard marks of students getting 50 and 60 marks. Also find the marks obtained corresponding to standard marks 1.30 and 1.50

Answer 1

Given : Number of Candidates - 15000

Mean marks = 40

Standard deviation marks = 8

To find :  Marks obtained corresponding to the standard marks 1.30 and 1.50.

Solution :

For 50 marks

score = ( Value - Mean )/ Standard Deviation

Z score  = ( 50  - 40)/8

= 10/8

= 5/4

For 60 Marks

Z score  = ( 60  - 40)/8

= 20/8

= 5/2

Thus, the standard marks of students scoring 50 marks = 1.25

the standard marks of student scoring 60 marks. =  2.5

For, marks 1.30 and 1.50.

1.3 = ( x - 40)/8

10.4 = x - 40

x = 50.4

and,

1.5 =  ( y - 40)/8

12 = y - 40

y = 52

Answer : The marks corresponding to standard marks 1.30 are 50.4 and 1.50 is 52.

Answer 2

Answer:

Sorry, I think the question is wrong..