an entrance examination for admission to a first degree course in medicine was conducted at the national level. the mean and standard deviation of marks obtained by 15000 candidates were 40 and 8, respectively. determine in terms of standard deviation, the standard marks of students getting 50 and 60 marks. also find the marks obtained corresponding to standard marks 1.30 and 1.50.
Answers
Given : an entrance examination for admission to a first degree course in medicine was conducted at the national level mean and standard deviation of marks 40 and 8, respectively.
To find : marks obtained corresponding to standard marks 1.30 and 1.50.
Solution :
Z score = ( Value - Mean )/ Standard Deviation
Mean = 40
SD = 8
for 50 Marks
Z score = ( 50 - 40)/8
=> Z = 10/8 = 5/4
For 60 Marks
Z score = ( 60 - 40)/8
=> Z = 20/8 = 5/2
the standard marks of students getting 50 and 60 marks. = 1.25 & 2.5 in terms of standard deviation
marks obtained corresponding to standard marks 1.30 and 1.50.
1.3 = ( value - 40)/8
=> 10.4 = Value - 40
=> Value = 50.4
1.5 = ( value - 40)/8
=> 12 = Value - 40
=> Value = 52
the marks obtained corresponding to standard marks 1.30 and 1.50.
= ( 50.4 & 52 )
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