An entry level price for Car A is R220 000, while an entry level price for Car B is approximately 81.818% of Car A. Explore Motors dealership has R7 million to spend and wants to buy equal numbers of the entry levels of Car A and Car B. What is the largest number of each type of car that can be bought?
Answers
Answer:
17
Step-by-step explanation:
CAR A = 220,000
CAR B = 81.818% of CAR A = 179,999.6
LET NUMBER OF CARS FOR EACH BE X
AMOUNT TO SPEND = 7,000,000
AX + BX = 7,000,000
220,000X + 179,999.6X = 7,000,000
399,999.6X = 7,000,000
X = 17.5
LARGEST NUMBER OF CARS = 17
Largest number of each type of car that can be bought is 17 where car A cost R220000 and Car B cost approximately 81.818% of Car A and equal number of cars to be bought with R7 million
Given:
- price for Car A is R220 000,
- price for Car B is 81.818% of Car A.
- Explore Motors dealership has R7 million to spend
- wants to buy equal numbers of the entry levels of Car A and Car B
To Find:
- The largest number of each type of car that can be bought
Solution:
Assume that largest number of each type of car that can be bought is N
Step 1:
Find Cost of N cars of type A
220000N
Step 2:
Find Cost of N cars of type B
81.818% of 220000N
=( 81818/100000 )220000N
= 179999.6N
Step 3:
Find Total Cost of N cars of Each type
220000N + 179999.6N
= 3,99,999.6N
Step 4:
Total Cost should be less than or equal to 7 million = 7000000
Solve for N
3,99,999.6N ≤ 7000000
=> N ≤ 17.5
As car can be in integers Hence
Largest number of each type of car that can be bought is 17
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