An envelope contains 20 sheets of paper which are numbered with the number 1 to 20. If anyone sheet is drawn random what is a probability that a sheet has a number that is factor of 20
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Solution(i):
Let E be event of drawing a card with number divisible by 2 or 3 from the cards with numbers 1 to 20
Numbers divisible by 2 or 3 from 1 to 20=2,3,4,6,8,9,10,12,14,15,16,18,20
No. of favorable outcomes=13
Total no. of possible outcomes =20
We know that, Probability P(E) =(Total no.of possible outcomes)(No.of favorable outcomes)=2013
Therefore, the probability that a number on the card selected from numbers 1 to 20 divisible by 2 and 3 is 2013
Solution(ii):
Let F be event of drawing a card with prime number from the cards with numbers 1 to 20
Prime numbers from 1 to 20=2,3,5,7,11,13,17,19
No. of favorable outcomes=8
Total no. of possible outcomes =20
We know that, Probability P(F) =(Total no.of possible outcomes)(No.of favorable outcomes)=208=52
Therefore, the probability that a card with prime number is selected from numbers 1,2,3,...,20 =52
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