Question

an enzyme contain 5.6% of Fe , calculate the no. of Fe atom present in 2.8 gram of enzyme.

Answer 1

Given weight of enzyme = 2.8 g

∴ weight of Fe atoms = 5.6% of 2.8 g = $\frac{5.6}{100} \times 2.8$

⇒ 0.16 g of Fe atoms are there

We know 1 mol Fe atoms weigh 55 g

Doing chain link conversions:

$\implies 0.16 \cancel{g} \times \frac{ 1\text{ mol of Fe}}{55 g} \times \frac{6.022 \times 10^{23}}{ \text{1 mol of Fe}}$

∴ We get :

$1.8 \times 10^{21}$ atoms of Fe in the enzyme