Question

an enzyme contains 11.2% Fe by mass. The no. of Fe atoms present in 1 g of enzyme is??

Answer 1

Answer:

The solution below will help uh..☺

Answer 2

Number of atoms of Fe in 1 gram of enzyme is 1.2×10²¹

GIVEN:

Mass % of Fe = 11.2%

TO FIND:

Number of fe atoms in 1 gram in enzyme.

Solution:

We can simply solve the problem as under -

It is given that 11.2% of Fe is present by mass

this means that,

11.2 grams of Fe is present in 100 grams of enzyme.

So, 100 grams of enzyme = 11.2 grams

So, 1 grams of enzyme will contain = 11.2 /100 = 0.112 grams of Fe.

Therefore,

the number of atoms present in 0.112 g of Fe can be calculated as =

$\frac{given \: mass}{molar \: mass \: of \: fe} \times na$

na = no of atoms in 1 mole of substance = 6.022 × 10²³

We know, that molar mass of Iron = 56 grams

putting the values in the above formula, we have -

=

$\frac{0.112}{56} \times 6.022 \times {10}^{23}$

=

$1.2 \times {10}^{21} atoms$

Hence Number of atoms of Fe in 1 gram of enzyme is 1.2×10²¹

#spj2