Question

an enzyme contains 2% of sulphur molecular weight of enzyme is 6400 number of Sulphur atoms in the enzyme​

Answer 1

TOPIC :- STOICHIOMETRY

SOLUTION :-

Given,

Given, the enzyme contains 2 % Sulphur .

Molecular mass of enzyme = 6400 gm

Hence, mass of sulphur in the enzyme = 6400 × 2℅

= 6400 × 2/100

= 128 gm

Now, mass of one sulphur atom = 32.

Hence, number of sulphur atom in 128 gm sulphur = 132/28 = 4.

Thus ,number of sulphur atom = 4.

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Answer 2

Your question is correct but the sentence allocation is bit confusing. The correct sentence formation for this would look like :

An enzyme contains 2% of sulphur molecular weight of enzyme is 6400.How many sulphur atoms are present in that enzyme molecule?

The sulphur atoms are present in that enzyme molecule is 4.

= Percentage of sulphur = weight of sulphur / molecular weight of sulphur * 100.

= 2 = weight of sulphur / 6400 * 100

= 2 * 6400 / 100

= 128g.

Then the number of sulphur atoms

= 128 / 32

= 4.

Therefore the sulphur atoms are present in that enzyme molecule is 4.