Question

An enzyme contains 5.6∘/∘Fe,if we calculate number of Fe atoms present in 1g of enzyme.​

Answer 1

Here is ur answer:

Mass of Fe =$\frac{5.6}{100} = 5.6 \times {10}^{ - 2} g$

Number of atoms =$\frac{5.6 \times {10}^{ - 2} }{56} \times 6.02 \times {10}^{23}$

$= 6.02 \times {10}^{23} atoms$

Hope this will help you ❤

Answer 2

Answer:

=6.02×10^23 atoms

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