Question

An equal number of laddoos have been placed in 3 different boxes. The laddoos in the first box were distributed among 20 children equally, the laddoos in the second box among 24 children and those in the third box among 12 children. Not a single laddoo was left over. Then, what was the minimum number of laddoos in the three boxes altogether?

Answer 1

Answer:

360

Step-by-step explanation:

Given An equal number of laddoos have been placed in 3 different boxes. The laddoos in the first box were distributed among 20 children equally, the laddoos in the second box among 24 children and those in the third box among 12 children. Not a single laddoo was left over. Then, what was the minimum number of laddoos in the three boxes altogether?

Now there are 3 different boxes containing laddoos. The first box was distributed among 20 children equally, the laddoos in the second box among 24 children and those in the third box among 12 children. So now we need to find the least number of laddoos. So we need to find the LCM of three numbers that is 20, 24 and 12.

So the factors are 2 x 2 x 3 x 5 x 2 x 1 = 120.

Now the laddoos altogether in 3 boxes will be 120 x 3 = 360

Answer 2

Answer:

Three boxes contain total of 27 laddus. The first and the second box together contain 15 in total. The second and the third box together contain 20 in total. How many laddus are there in the first and the third box together?