Question

An equiconvex lens has a power of 5 dioptre. If it is

made of glass of refractive index 1.5. then radius

of curvature of its each surface will be ?

(1) 20 cm (2) 10 cm (3) 40 cm (4)

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Answer 1

Answer:

Radius of curvature = 10 m

Explanation:

n = 1.5

P = 1 /f

P = 5 D, f = 1/5 m

$\frac{1}{f} = (n - 1) [ \frac{1}{R_{1} } - \frac{1}{R_{2} } ]$                       ( $\frac{1}{R_{1} }$ = $\frac{1}{R_{2} }$ = $\frac{1}{R}$ , Lens is equiconvex )

5 = ( .5 ) [ 2/R ]

5 / .5 = 2 /R

.1 = 1 /R

R = 10 m

Answer 2

Answer:

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