Physics, asked by storeofmumbai8629, 10 months ago

An equilateral prism is made up of material of refractive index √3. The angle of minimum deviation of light passing through the prism is_________.

Answers

Answered by Fatimakincsem
52

Answer:

The answer is 60°

Explanation:

Refractive index of a prism is given by the eq uation.

Refractive index   = [Sin{A+DM}/2]/SinA/2

= Sin[{60+Dm}/2]/Sin(60/2)=√3

= Sin{30+(Dm/2)}/Sin30=√3

= Sin{30+(Dm/2)}×2=√3

= 30+(Dm/2)= Sin-1(√3/2)=60°= Dm/2 = 60°–30

Dm =30×2=60°

Answered by Jasleen0599
7

Given:

An equilateral prism.

⇒ A = 60°

The refractive index of the prism, μ = √3

To Find:

The angle of minimum deviation of light passing through the prism.

Calculation:

- We know that the refractive index can be given as:

μ = sin {(A+δ_{m})/2} / sin (A/2)

⇒ √3 = sin {(60+δ_{m})/2} / sin (60/2)°

⇒ sin {30° + (δ_{m}/2)} = √3 × sin 30°

⇒ sin {30° + (δ_{m}/2)} = √3/2

⇒ 30° + (δ_{m}/2) = sin⁻¹(√3/2)

⇒ δ_{m}/2 = 60° - 30°

⇒ δ_{m} = 30° × 2

δ_{m} = 60°

- So, the angle of minimum deviation of light passing throughh the prism is 60°.

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