Question

an equilateral prism produces a minimum deviation of 40degree in air what is the refractive index of the prism?if the prism is placed inside water of refractive index 1.33 what will be the new minimum deviation angle? pls ans this on ray optics​

Answer 1

Explanation:

ANSWER

Minimum deviation δ=2i−A

where A is prism angle A=60

o

For minimum angle the angle of refraction should be half of prism angle.

So r=A/2=30

o

now using the snell's law

n

water

sini=n

glass

sinr

1.33sini=1.53sin30

i=35.11

o

Minimum deviation δ=2i−A

δ=2×35.11−60=10.2

o