An equilateral triangle ABC is inscribed in a circle with center o. What will be the measure of /boc
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join ob, oc
now in the triangle boc
angle obc = 1/2 angle b = 1/2 * 60 = 30
angle ocb = 1/2 angle c = 1/2 * 60 = 30
using angle sum property we can find angle boc
angle boc + angle obc + angle ocb = 180
angle boc + 30 + 30 = 180
angle boc + 60 = 180
angle boc = 180 - 60
angle boc = 120
now in the triangle boc
angle obc = 1/2 angle b = 1/2 * 60 = 30
angle ocb = 1/2 angle c = 1/2 * 60 = 30
using angle sum property we can find angle boc
angle boc + angle obc + angle ocb = 180
angle boc + 30 + 30 = 180
angle boc + 60 = 180
angle boc = 180 - 60
angle boc = 120
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