Question

An equilateral triangle abc of side 20 cm is given below. A semi circle is drawn by considering the bc as diameter. The semi circle meets ab at d, and ac at
e. Find the area of the shaded region.

Answer 1

Answer:

16.06

Step-by-step explanation:

area of equilateral triangle =

$\sqrt{3} {a}^{2} \div 4$

=root3×20×20/4

$100 \sqrt{3}$

=173.2cm^2

area of semicircle=

$\pi {r}^{2} \div 2$

=22/7 × 10×10 ÷2

=1100/7

=157.14cm^2

area of shaded region =173.2 - 157.14=16.06 cm^2