Question

An equilateral triangle BPC is drawn inside a square ABCD what is the value of ⎳ in degrees?

Answer 1

Answer:

PBC = ∠CPB = ∠BPC (equilateral triangle) and PC = CD = a.

CPD = ∠ PDC = 75 [(180 – 30)/2]

Similarly, ∠BAP = ∠BPA = 75

Hence ∠APD = 360 – (75 +75 + 60) = 150

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Answer 2

Answer:

if its an Equilateral Triangle , all angles are 60 Degrees , no matter how and where we draw BPC . angles are as follows

angle ABP  = ANGLE PCD 30 DEGREES

ANGLE BAP  = ANGE PDC= 90 DEGREES

ANGLE BPA= ANGLE CPD=60 DEGREES

AND INTERNAL ANGLES OF TRIANGLE ARE ALL 60 DEGREES.

THANKS for making question intelligent by no enclosing piture. :). hpy to be freinds with you !

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