Question

an equilateral triangle has a side of 22/7cm find the perimeter of the triangle​

Answer 1

Hey,

Given area of inscribed circle = 154 sq cm

Let the radius of the incircle be r.

⇒ Area of this circle = πr2 = 154

(22/7) × r2 = 154

⇒ r2 = 154 × (7/22) = 49

∴ r = 7 cm

Recall that incentre of a circle is the point of intersection of the angular bisectors.

Given ABC is an equilateral triangle and AD = h be the altitude.

Hence these bisectors are also the altitudes and medians whose point of intersection divides the medians in the ratio 2 : 1

∠ADB = 90° and OD = (1/3) AD

That is r = (h/3)

Þ h = 3r = 3 × 7 = 21 cm

Let each side of the triangle be a, then

Altitude of an equilateral triangle is (√3/2) times its side

That is h = (√3a/2)

∴ a = 14√3 cm

We know that perimeter of an equilateral triangle = 3a

= 3 × 14 √3 = 42√3

= 42 × 1.73 = 72.66 cm

:)

Answer 2

Explanation:

To find the perimeter of an equilateral triangle given its area, we must first find the length of the sides. This can be done by using the equation of the area of an equilateral triangle:

Area=a23–√4

where a is the side of the triangle.

Because the sides of the equilateral triangle are equal, the perimeter is equal to 3a.
answer is 33.8....


hope it is helpful to you