An equilateral triangle has been inscribed in a circle of radius 6 cm
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Let ABC is an equi.triangle inscribed
in a circle of radius 6cm and centre o
join o to a and o to b
angle AOB =360/3
=120
in triangle AOB
AOB=(oa^2+ob^2-ab^2)/2.is.ob
120°=(6^2+6^2-ab^2)/2×6×6
-1/2=(36+36-ab^2)2×36
-1/1=72-ab^2/36
-36=72-ab^2
ab^2=72+36
=108
ab=6.(3)^1/2cm..
in a circle of radius 6cm and centre o
join o to a and o to b
angle AOB =360/3
=120
in triangle AOB
AOB=(oa^2+ob^2-ab^2)/2.is.ob
120°=(6^2+6^2-ab^2)/2×6×6
-1/2=(36+36-ab^2)2×36
-1/1=72-ab^2/36
-36=72-ab^2
ab^2=72+36
=108
ab=6.(3)^1/2cm..
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