an equilateral triangle has each side 2 m . with all the three corners as center circles are described each of radius one metre. find the area of the remaining portion of the triangle.
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Side of Equilateral Triangle = 2 m
Area of Triangle = A = √3/4 a²
= √3 / 4 × 2 × 2
= √3 m²
Radius = 1 m
Area of 3 sector
= 3 × πr²ø / 360
= πr²ø / 120
= 22/7 × 1 × 1 × 1 × 60 / 120
= 22 / 7 × 1 / 2
= 11 / 7
= 1.57 m²
Area of Shaded Portion
= Area of Triangle - Area of 3 Sector
= 1.73 - 1.57
= 1.6 m²
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Area of Triangle = A = √3/4 a²
= √3 / 4 × 2 × 2
= √3 m²
Radius = 1 m
Area of 3 sector
= 3 × πr²ø / 360
= πr²ø / 120
= 22/7 × 1 × 1 × 1 × 60 / 120
= 22 / 7 × 1 / 2
= 11 / 7
= 1.57 m²
Area of Shaded Portion
= Area of Triangle - Area of 3 Sector
= 1.73 - 1.57
= 1.6 m²
Hope you like it please mark as brainliest and follow me if you like it.
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Answered by
1
triangle's side=2m
area=√3/4×(2×2)
=√3=1.73
area of the circle
=π×(1/√3)2
=π×1/3=3.14/3=1.04
area of remaining part
=1.73-1.04
=.69m
area=√3/4×(2×2)
=√3=1.73
area of the circle
=π×(1/√3)2
=π×1/3=3.14/3=1.04
area of remaining part
=1.73-1.04
=.69m
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