Question

an equilateral triangle has each sides 10 cm .find the area of the triangle​

Answer 1

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Answer 2

Let A,B and C be the vertices of the equilateral triangle and M the midpoint of segment BC. Since the triangle is equilateral, AMC is a right triangle. Let us find h the height of the triangle using Pythagorean theorem.

$h^{2}$ + $5^{2}$ = $10^{2}$

Solve the above equation for h.

h = 5 sqrt(3) cm

We now find the area using the formula.

area = (1/2)* base * height = (1/2)(10)(5 sqrt(3))

= 25 sqrt(3) $cm^{2}$ = 43.3 $cm^{2}$