an equilateral triangle is inscribed in a circle of radius 10cm find area of triangle
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Answered by
2
triangle is equilateral
tan30=1/root3
=x/10
therefore x=10 root3
area = 6 * area of right angle triangle
area = 6* 1/2*10 root 3* 10
area =300 root 3
Answered by
1
let ABC be the equilateral triangle and circle with centre O touching triangle at point P,Q and R.
join OR.
Now in triangle OQC
tan30=OQ/QC = 1/√3=10/QC
=QC=10√3
and BC=20√3
area of equilateral triangle=√3/4*a²
=√3/4*20√3*20√3
=300√3cm²
join OR.
Now in triangle OQC
tan30=OQ/QC = 1/√3=10/QC
=QC=10√3
and BC=20√3
area of equilateral triangle=√3/4*a²
=√3/4*20√3*20√3
=300√3cm²
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