Question

An equilateral triangle of each side 4.18 cm is made of a wire. If the same piece of wire is bent into a ring.
Find the diameter.​

Answer 1

Answer:

Step-by-step explanation:

total length of the wire = 4.18 x 3= 12.54cm

circumference of the ring = 2 x pi x r= 12.54  where r is the radius of the circle

r =(12.54 x 7)/(2x 22)= 1.995

diameter of the circle= 1.995 x 2= 3.99cm

Answer 2

$\huge\bold\blue{Question}$

An equilateral triangle of each side 4.18 cm is made of a wire. If the same piece of wire is bent into a ring. Find the diameter.

$\huge\bold\blue{Answer}$

$\tt{Side \:of \:the \:equilateral \:triangle\: = 4.18 cm }$

$\tt\red {Perimeter \:of\:Triangle\:=\:3\:×\:side}$

$\tt{Perimeter \:of \:equilateral \:triangle\: = 3 × 4.18 }$

⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀$\tt {= 12.54 cm }$

$\tt{According \:to \:the\: question}$

$\tt{Same \:piece\: of\: wire \:bent \:into\: a \:ring }$

$\tt{so...\: we \:will \:take..}$

$\tt{Perimeter \:= \:Circumference }$

$\tt{Now,}$

$\tt\red {Circumference \:of\:circle\:=\:2πr}$

$\tt {Circumference \:of \:ring\: = 2πr}$

--->⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀$\tt {12.54 = 2 × 22/7 × r}$

--->⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀$\tt {12.54 = 44/7 × r}$

--->⠀⠀ ⠀⠀⠀⠀⠀⠀$\tt {12.54 × 7 = 44r}$

--->⠀⠀ ⠀⠀ ⠀⠀⠀⠀⠀⠀$\tt {87.78 = 44r}$

--->⠀ ⠀ ⠀⠀⠀⠀⠀$\tt {87.78 ÷ 44 = r}$

--->⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀$\tt {r = 1.995 cm}$

$\tt {radius\: = 1.995 cm}$

$\tt {hence,}$

$\tt{Diameter\: = 2 × \:radius}$

⠀⠀⠀ ⠀⠀$\tt {= 2 × 1.995 }$

⠀ ⠀⠀ ⠀⠀$\tt {= 3.99 cm}$