An equilateral triangle of side 2m is placed in a electric field of E=10NC
Find the potential difference between point A and B.
(a)20V
(b)10V
(c)15V
(d)25V
Answers
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Answer = 20V
We know E=V/D
E=10V
D=2
10=V/2
V=20
So Va – Vb = 20
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