Physics, asked by ishanimaz, 6 months ago

An equilateral triangle of side 2m is placed in a electric field of E=10NC

Find the potential difference between point A and B.
(a)20V
(b)10V
(c)15V
(d)25V​

Answers

Answered by Saratchandragarnayak
7

Answer = 20V

We know E=V/D

E=10V

D=2

10=V/2

V=20

So Va – Vb = 20

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