An equilateral triangle of side 6 cm is inscribed in a circle. Find the radius of the circle
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Given : ABC is equilateral triangle.
OC= radius of cicle. ∠ACP=60
∘
BC=6cm (Given) ∠OCP=
2
∠ACP
=30
∘
.
PC=
2
BC
=3cm
in ΔOPC :-
cos∠OCP=
OC
PC
⇒cos30
∘
=
OC
PC
⇒
2
3
=
OC
3
⇒OC=2
3
cm
∴ Radius of circle OC=2
3
cm
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