An equilateral triangle of side 6 cm is inscribed in a circle. Find the radius of the circle.
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We know that for an equilateral triangle, Height (perpendicular) = (√3/2).(side)
We know that for an equilateral triangle, Height (perpendicular) = (√3/2).(side)Here, Height = (√3/2).S
we now get that length of the line segment denoted by “a” = (2/3)
Height = T (2/3).(√3/2)
S =(S/ √3) = Radius
Radius = (6/ √3)
= 2√3 cm
Hope this helps you..
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