Question

an equilateral triangle of side 6 cm is inscribed in a circle.Find the radius of the circle.​

Answer 1

Step-by-step explanation:

$oc = radius \: of \: he \: circle \\ bc = 6cm \\ pc = \frac{6}{2} = 3cm$

<ACP = 60°

<OCP = ACP/3

30°

$in \: triangle \: opc \\ \cos(30) = \frac{pc}{oc} \\ \ \frac{ \sqrt{3} }{2} = \frac{pc}{oc} \\ oc = 2 \sqrt{3}$