An equilateral triangle of side 9 cm is inscribed in a circle find the radius of the circle.
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9^2 = r^2 + r^2 - 2*r*r*cos(120)
81 = 2r^2 - 2r^2*(-0.5)
81 = 2r^2 + r^2
3r^2 = 81
r^2 = 81/3
r^2 = 27
r = sqrt(27)
r = 3*sqrt(3)
r =~ 5.1961524227066318805823390245176
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