An equilateral triangle of side 9cm is inscribed in a circle. Find the radius of the circle. Find it immediately
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LET TRIANGLE ABC IS EQUILATERAL TRIANGLE OF SIDE 9 CM AND AD IS THE MEDIAN WHERE G IS THE CENTROID OF TRIANGLE WHICH DIVIDES MEDIAN INTO 2:1
GD PERPENDICULAR TO BC
IN RIGHT ANGLE TRIANGLE ADB
AD²+DB²=AB² WHERE AB=9 CM AND BD= 4.5CM
AD²+(9/2) ²=9²
AD²=81-81/4
AD²=243/4
AD=√243/4
AD=9√3/2
RADIUS =2/3 AD=2/3×9√3/2=3√3CM
THEREFORE 3√3 IS THE RADIUS OF CIRCLE
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bahe bhosdi ke madarchod
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