An equilateral triangle of side 9cm is inscribed in a cirlce.Find the radius of the circle
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Let ABC be an equilateral triangle of side 9cm and let AD one of its medians. Let G be the centroid of ΔABC.
Then AG : GD = 2:1
WKT in an equilateral Δle centroid coincides with the circum center
Therefore, G is the center of the circumference with circum radius GA
Also G is the center and GD ⊥ BC .
Therefore,
In right triangle ADB, we have
(AB)2 =(AD)2+( DB)2
(9)2=(AD)2+(DB)2
=AD=3ROOT3CM
Then AG : GD = 2:1
WKT in an equilateral Δle centroid coincides with the circum center
Therefore, G is the center of the circumference with circum radius GA
Also G is the center and GD ⊥ BC .
Therefore,
In right triangle ADB, we have
(AB)2 =(AD)2+( DB)2
(9)2=(AD)2+(DB)2
=AD=3ROOT3CM
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ayush4201:
can you elongate WKT
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