an equilateral triangle whose each side is of a cm is rotated along a side as an axis then what is the area of the figure formed by it
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If an equilateral triangle of side a is rotated along an axis it forms 2 3D cones with a common base.
Area of a cone = pie × r× l
= pie × a/2 × a
= 22/7 ×a/2 × a
= 11/7 a^2 sq cm
Hence area of the 3D shape formed is 2 area
= 22/7 a^2 sq cm
Step-by-step explanation:
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