Physics, asked by tilak24, 1 year ago

An eraser of weight 2N is pressed against the black board with a force of 5N. If the coefficient of friction is 0.4.How much force parallel to the black board is required to slide the eraser upwards

Answers

Answered by yadav1999anurapegxdq
31

As,  F=w+uf=2+[0.4*5]=2+2=4N


tilak24: how f=uF
yadav1999anurapegxdq: Should I explain or u got ur answer
tilak24: explain
yadav1999anurapegxdq: Acc to u
tilak24: sry
tilak24: i didn't understood
yadav1999anurapegxdq: f is the force required to push the body and
yadav1999anurapegxdq: F is the resistive force which opposes force f
tilak24: my doubt is how f=uf i know it f=uN
yadav1999anurapegxdq: So, f =coefficient of friction + resistive force
Answered by srikanth249
5

Answer:

4N is the answer I think so

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