Question

an eraser weighing 2N is pressed against the black board with a force of 5 Newton if the coefficient of friction is 0.4 how much force parallel to the blackboard is required to slide there is reports

Answer 1

application of friction on vertical surface

Answer 2

Answer:

The minimum force required to move the eraser is 4 N

Explanation:

The weight of the eraser is w=2 N along negative y-axis

The force applied perpendicular to the black board is F=5 N is along positive x-axis

The coefficient of friction is $\mu=0.4$

The frictional force acts between the eraser and the black board is along negative y-axis

The normal reaction N is along the negative x-axis

The minimum force $F_{m}$ required to move the eraser is along positive y-axis

The normal reaction N=F=5 N

The frictional force is

$f=\mu N\\f=0.4\times 5\\f=2\ N$

Balancing equation along y-axis we have,

$F_{m}=w+f\\F_{m}=2+2\\F_{m}=4\ N$