An erect image 2cm high is formed 12 cm from the lens whose power is 25/3 D. If the Object is 3cm high, calculate the distance of the object from its image.
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Answer:
Focal length of the lens is 4 cm.
Explanation:
It is given that,
Height of image, h' = 2 cm
Image distance, v = -12 cm
Height of object, h = 0.5 cm
We have to find the focal length of the lens. It is a convex lens because the image is large as compared to object. Firstly calculating magnification of lens as :
Explanation:
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