Question

an erect image 3 times of the size of the object is obtained with the concave mirror of radius of curvature of 36 cm calculate the position of the object​

Answer 1

hope this helps u  

magnification m  = - v/u = h'/h  = +3

      v = -3 u        actually  u is negative.  Hence v is positive.

      R = -36 cm    =>  f = R/2 = -18 cm , negative for a concave mirror.

      1/v + 1/u = 1/f,   mirror equation

       1/(-3u)  + 1/u = 1/(-18)

       2/(3u)  = -1/18

       

          u = - 12 cm    v = +36 cm 

 the object is placed 12 cm from pole of concave mirror ,  less than the focal length, to have an ERECT magnified image 3 times the object.

 

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Answer 2

Answer:

see below

Step-by-step explanation:

hope this helps u  

magnification m  = - v/u = h'/h  = +3

     v = -3 u        actually  u is negative.  Hence v is positive.

     R = -36 cm    =>  f = R/2 = -18 cm , negative for a concave mirror.

     1/v + 1/u = 1/f,   mirror equation

      1/(-3u)  + 1/u = 1/(-18)

      2/(3u)  = -1/18

       

         u = - 12 cm    v = +36 cm  

the object is placed 12 cm from pole of concave mirror ,  less than the focal length, to have an ERECT magnified image 3 times the object.