Question

An erect image 3 times size of object is obtained with concave mirror of Radius of cuerature to is 36 cm What is position of object
solve with full method
A 12cm
B - 12cm
C 24cm​
D -24

Answer 1

focal length = f = 15cm

Height of image (hi) = 3 x height of object (hi)

q = 3p (where q is image distance and p is object distace) ; As hi/ho = q/p

p = ??

1/f = 1/p + 1/q (formula)

1/15 = 1/p + 1/3p

1/15 = 4/3p

p = 15(4)/3

p = 20cm

Result: object distance is 20cm from the lens.

Explanation:

please follow me and make brainlist

I am new user...