An erect image 3 times the size of the object is obtained with a concave mirror of radius of curvature Tata centimetre what is the position of
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Magnifiation=(focal length-v)/focal length
3={(radius of curvature/2)-v}/(radius of curvature/2)
hope this helps!
pls fill the radius of curvature urself as it is not mentioned properly in the question!
3={(radius of curvature/2)-v}/(radius of curvature/2)
hope this helps!
pls fill the radius of curvature urself as it is not mentioned properly in the question!
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