Question

An erect image 3 times the size of the object is obtained with the concave Mirrors of a radius of curvature 36 cm what is the position of the object​

Answer 1

Answer:

Answer Expert Verified

R = -36 cm => f = R/2 = -18 cm , negative for a concave mirror. the object is placed 12 cm from pole of concave mirror , less than the focal length, to have an ERECT magnified image 3 times the object.

Answer 2

Answer:

For an erect image, magnification is positive. Thus, m = 3 for an erect image three times the size of the object. m = 3 For a concave mirror, m = −vu=3⇒−vu=3⇒v = -3u Using Mirror formula, 1v+1u=1f1v+1u=1f Thus, the image is formed behind the mirror at a distance of 36 cmRead more on Sarthaks.com - https://www.sarthaks.com/936646/erect-image-three-times-object-formed-with-concave-mirror-radius-curvature-position-image